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An electron is projected as shown in fig...

An electron is projected as shown in fig. with kinetic energy K, at an angle `theta=45^(@)` between two charged plates. Ignore the gravity.

At what distance from the starting point will the electron strike the lower plate?

A

d

B

2d

C

3d

D

4d

Text Solution

Verified by Experts

The correct Answer is:
D
`d=(u^(2)sin^(2)theta)/(2a) [a=(qE)/(m)]`
`=(m u^(2)sin^(2)45^(@))/(2qE)`
`d=(K)/(2qE) or, E=(K)/(2dq)`
`R=(u^2)/(a) = (2d)/(sin^(2)theta)=4d`
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