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Consider Gauss's law oint vecE * vecd ...

Consider Gauss's law
`oint vecE * vecd s = q/epsilon_0`
Then, for the situation shown in figure at the Gaussian surface

A

`vecE due to q_2` would be zero.

B

`vecE` due to both `q_1 and q_2` would not be zero

C

`phi` due to both `q_1 and q_2` would not be zero.

D

`phi` due to `q_2` would be zero.

Text Solution

Verified by Experts

The correct Answer is:
B, D
In `LHS` of Gauss's law , `vec€` is due to all point charges present in space and `phi` depends only on the enclosed charges.
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