Gauss's law and Coulomb's law , although expressed in different forms , are equivalent ways of describing the relation between charge and electric field in static conditions . Gauss's law is `epsilon_(0) phi = q_(encl)`,when `q(encl)` is the net charge inside an imaginary closed surface called Gaussian surface. The two equations hold only when the net charge is in vaccum or air .
If the charge `q_(3)` and `q_(4)` are displaced (always remaining outside the Gaussian surface), then consider the following two statements :
`A`: Electric field at each point on the Gaussian surface will remain same .
`B`: The value of `oint vec(E ) .d vec(A)` for the Gaussian surface will remain same.

Options

A. Both `A` and `B` are true .
B. Both `A` and `B` are false.
C. `A` is true , but `b` is false.
D. `B` is true , but `A` is false.

Answer

D

Explanation

Electric field will change since two of the charges are displaced from their earlier position , while flux will not change since `q_(1)` and `q_(2)` are still inside the surface.