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A uniform electric field is present in t...

A uniform electric field is present in the positive x - direction. If the intensity of the field is `5 NC^-1` then find the potential difference `(V_B - V_A)` between two points A (0 m, 2 m) and B (5 m, 3 m).

Text Solution

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we know potential difference between points A and B in uniform electric field is `V_B - V_A = - vec(E) . vecA B`. Here we are given `vec(E) = 5 hat(i) (Vm^-1)` and
`vec A B = (5 - 0) hat(i) + (3 - 2) hat(j) (m)`
Hence, `V_B - V_A = -(5 hat(i)).(5 hat(i) + hat(j))= - 25 V`.
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Knowledge Check

  • A uniform electric field to 100 Vm^(-1) is directed at 60^@ with the positive x-axis as shown in figure. If OA= 2 m, the potential difference V_O - V_(A) is

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  • Figure shows the variation of electric field intensity E with distance x. The potential difference between the point x = 0 and x= 5m is

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