If 0.6 mol of electorns flows throutgh a wire in 45 min, what are (a) the total charges that passes through the wire and (b) the magnitude of the current?

Explanation

a. The number N of electrons in 0.6 mol is
`N =(0.6mol)(6.02xx10^(23)"electrons"//"mol"^(-1))`
`=3.6xx10^(23)"electrons"`
`q = Ne = (3.6xx10^(23))(1.6xx10^(-19)) = 5.78xx10^4`
b. `t = (45min)(60smin^(-1)) = 2.7xx10^3S`
`I = (q)/(t) = (5.78x10^4)/(2.7xx10^3Cs)=21.4A`