A galvenometer has a resistance of `50 Omega` and its full - scale deflaction current is `mu A`. What shunt resistance should be added so that the ammeter can have a range of `0-5 mA`?
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Given `I_(G) = 50 mu A`. The upper limit gives the maximum currect to be measured, which is `I = 5 mA`. The galvanomenter , resistance is `G = 50 Omega`. Now `S = (I_(G)G)/(I - I_(G)) = (50 xx 10^(-6) xx 50)/(5 xx 10^(-3) - 50 xx 10^(-6)) = (50 xx 10^(-6) xx 50)/(5 xx 10^(-3)) ~~ 0.5 Omega`
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