What is the value of the shunt that passes `10%` of the main current through a galvenomenter of `99 Omega`?
Text Solution
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Given `G = 99 Omega` and `I_(G) = (10//100) I = 0.1I` Now `S = (I_(G) G)/(I - I_(G)) = (0.1I xx 99)/((I - 0.1I)) = (0.1)/(0.9) xx 99 = 11 Omega`
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