Home
Class 12
PHYSICS
A battery is connected to a potentiomete...

A battery is connected to a potentiometer and a balance point is obtained at `84 cm` along the wire. When its terminals are connected by a `5 Omega` resistor, the balance point changes to `70 cm`.
Find the new position of the balance point when `5 Omega` resistor is changed by `4 Omega` resistor.

A

`26.5 cm`

B

`52 cm`

C

`67.2 cm`

D

`83.3 cm`

Text Solution

Verified by Experts

The correct Answer is:
C

`r = (l_(1) - l_(2))/(l_(2))R = (84 - 70)/(70) xx 5 = 1 Omega`
`1 = (l_(1) - l_(3))/(l_(3)) xx 4`, put `l_(1) = 84 cm` get `l_(3) = 67.2 cm`
Promotional Banner

Topper's Solved these Questions

  • ELECTRICAL MEASURING INSTRUMENTS

    CENGAGE PHYSICS|Exercise Integer|8 Videos
  • ELECTRICAL MEASURING INSTRUMENTS

    CENGAGE PHYSICS|Exercise M.C.Q|2 Videos
  • ELECTRICAL MEASURING INSTRUMENTS

    CENGAGE PHYSICS|Exercise Assertion-Reasoning|7 Videos
  • ELECTRIC POTENTIAL

    CENGAGE PHYSICS|Exercise DPP 3.5|14 Videos
  • ELECTROMAGENTIC INDUCTION

    CENGAGE PHYSICS|Exercise QUESTION BANK|40 Videos

Similar Questions

Explore conceptually related problems

A battery is connected to a potentiometer and a balance point is obtained at 84 cm along the wire. When its terminals are connected by a 5 Omega resistor, the balance point changes to 70 cm . Calculate the internal resistance of the cell.

In a potentiometer, balance point is obtained, when

In a potentiometer of 5 wires, the balance point is obtained on the 3rd wire. To shift the balance point to the 4th wire,

For a cell of e.m.f. 2 V , a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a 2Omega resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is

In a metre bridge, the gaps are closed by two resistance P and Q and the balance point is obtained at 40 cm . When Q is shunted by a resistance of 10 Omega , the balance point shifts to 50 cm . The values of P and Q are. .

125 cm of potentiometer wire balances the emf. of a cell and 100 cm of the wire is required for balance, if the poles of the cell are joined by a 2 Omega resistor. Then the internal resistance of the cell is

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10Omega is connected in parallel to the cell, the balancing length changes by 60 cm. Find the internal resistance of the cell.

In a meter bridge experiment when a resistance wire is connected in the left gap, the balance point is found at the 30^(th) cm. When the wire is replaced by another wire,t he balance point is found at the 60^(th) cm. Find the balance point when the two wires connected in parallel in the left gap successively

A potentiometer is connected across A and B and a balance is obtained at 64.0 cm . When the potentiometer lead at B is moved to C , a balance is found at 8.0 cm . If the potentiometer is now connected across B and C , a balanced will be found at

When an unknown resistance and a resistance of 4Omega are connected in the left and right gaps of a meterbridge, the balance point is obtained at 50 cm. the shift in the balance point if a 4Omega resistance is now connected in parallel to the resistance in the right gap is