The ammeter shows in Fig. 6.73. Consists of `480 Omega` coil connected in parallel to `20 Omega` shunt. The reading of the ammeter comes out to be `1//'**'A`. What is '**'?

Answer

`(8)`

Explanation

Equivalent resistance of the ammeter is
`((480)(20 Omega))/(480 Omega + 20 Omega) = 19.2 Omega`
The equivalent resistance of the circuit is `140.8 Omega + 19.2 Omega = 160 Omega`. Therefore, current, `I = 20 V//160 Omega = (1//8) A`