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In the circuit shows in Fig. 6.74, the i...

In the circuit shows in Fig. 6.74, the internal resistance of the cell is negligible. For the value of `R = 40//x Omega`, no current flows through the galvanometer. What is `x`?

Text Solution

Verified by Experts

The correct Answer is:
`(9)`
`(V - 2)/(40) = (2 - 0)/(40)` or `V = 4`
`I_(1) = (2)/(40) = 0.05 A`
`:. (V - 2)/(R ) = 0.45`
or `R = (4 - 2)/(0.45) = (2)/(0.45) = (40)/(9) Omega`
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