Two bulbs are rated `30 W - 200 V and 60 W - 200 V`. They are connected with a `400 V` power supply. Find which bulb will get fused if they are connected in (i) series and (ii) parallel.

Explanation

`R_(1) = ((200)^(2))/( 30) Omega , R_(2) = ((200)^(2))/(60) Omega rArr R_(1) gt R_(2)`
Hence, voltage across the first bulb will be greater than `200 V` . So it will get fused.
(ii) In parallel, potential across both the bulbs will be same and equal to `400 V`. So both will get fused.