A dry cell of emf `1.5 V` and internal resistance `0.10 Omega` is connected across a resistor in series with a very low resistance ammeter. When the circuit is switched on , the ammeter reading settles to a steady value of `2.0 A`.
(i) What is the steady rate of chemical energy consumption of the cell ?
What is the steady rate of energy dissipation inside the cell ?
(ii) What is the steady rate of energy dissipation inside the cell ?
(ii) What is the steady rate of energy dissipation inside the resistor ?
(iv) What is the steady power out put of the source?

Explanation

rate of chemical energy consumption of the cell is
`EI = 1.5 xx 2 = 3 W`
(ii) Rate of energy dissipation inside the cell is
`I^(2) r = (2)^(2) xx 0.1 = 0.4 W`
(iii) Rate of energy dissipation inside the resistor is
`I^(2)R = EI - I^(2) r = 3 - 0.4 = 2.6 W`
(iv) Power out `= I^(2)R = 2.6 W`