Two bulbs are marked `200 V, 300 W and 200 V, 600 W`, respectively. The bulbs are connected in series and the combination is connected to a `200 V` supply .
(a) Which bulb will produce more illumination ?
(b) Find the total power consumed by both the bulbs.
(c ) Find the total power consumed if both the bulbs were connected in parallel.

Explanation

(a) `R_(1) = (200^(2))/( 300) , R_(2) = ( 200^(2))/(600)`
The resistance of the first bulb is more. Hence, in series , the first bulb will produce more illumination.
(b) `P = ( P_(1)P_(2))/( P_(1) + P_(2)) = ( 300 xx 600 ) /( 300 + 600 ) = 200 W`
(c) `P = P_(1) + P_(2) = 300 + 600 = 900 W`