Three identical resistors are connected in series . When a certain potential difference is applied across the combination , the total power would be dissipated is `27 W`. How many times the power would be dissipated if the three resistors were connected in parallel across the same potential difference ?

Answer

9

Explanation

For three identical resistors in series , `P_(s) = V^(2)// 3 R `. If they are now in parallel over the same voltage ,
`P_(p) = (V^(2))/(R_( eq)) = (V^(2))/(R//3) = ( 9 V^(2))/( 3 R) = 9P_(s) = 9 xx ( 27 W)`