Home
Class 12
PHYSICS
A heating coil is rated 100 W , 200 V. T...

A heating coil is rated `100 W , 200 V`. The coil is cut in half and two pieces are joined in parallel to the same source . Now what is the energy `( "in" xx 10^(2) J)` liberated per second?

Text Solution

Verified by Experts

The correct Answer is:
4
Let resistance of heating coil be `R` , then
`100 = (200^(2)) /(R ) or R = ((200)^(2))/(100) Omega`
Resistance of each cut part is `R//2`. Now , power dissipated is
`P = 2(((220)^(2)) / ( R//2))`
`= 4 ((220)^(2))/( R ) = 4 xx 100 = 400 W`
Promotional Banner

Topper's Solved these Questions

  • HEATING EFFECT OF CURRENT

    CENGAGE PHYSICS|Exercise Calculating Thermal Power in Resistance|14 Videos

  • HEATING EFFECT OF CURRENT

    CENGAGE PHYSICS|Exercise Thermal Power in Resistance Connected in Circuit|28 Videos

  • HEATING EFFECT OF CURRENT

    CENGAGE PHYSICS|Exercise Comprehension|13 Videos

  • GRAVITATION

    CENGAGE PHYSICS|Exercise Question Bank|39 Videos

  • INDUCTANCE

    CENGAGE PHYSICS|Exercise Concept Based|9 Videos

Similar Questions

Explore conceptually related problems

A heating coil is labelled 100 W, 220 V, the coil is cut in half and two pieces are joined in parallel to the same source. t/he energy now liberated per second is

A heating coil is labelled 100 W, 220 V . The coil is cut in two equal halves and the two pieces are joined in parallel to the same source. The energy now liberated per second is

A heater coil is rated 100W,200V. It is cut into two identical parts. Both parts are connected together in parallel, to the same sources of 200V. Calculate the energy liberated per second in the new combination.

A heater coil is rated 100W,200V. It is cut into two identical parts. Both parts are connected together in parallel, to the same sources of 200V. Calculate the energy liberated per second in the new combination.

A heating coil transforms 100J of electrical energy into heat energy per second. The coil is cut into two halves and both the halves are joined togeter in parallel to the same source. Now the energy transformed per second will be

Two electric bulbs A and B are rated 60 and 100 W , respectively. If they are connected in parallel to the same source , then

Two electric bulbs A and B are rated as 60 W and 100 W . They are connected in parallel to the same source. Then,

A 100 W heater coil is rated 200 V. Find the resistance of thwe coil.