The electric potetnial in a region along x-axis varies with `x` according to the releation `V(x) = 4 xx 5x^(2)`. Then the incorrect statement is

Options

A. potential difference between the points x = 1 and x = -2 is 15 V.
B. the force experienced by the above charge will be towards the +x-axis.
C. a uniform electric field exists in this region along the +x-axis.
D. force experienced by a 1 C charge at x = -1 will be 10 N.

Answer

A, C, D

Explanation

a.,c.,d.
`V(x)=4+5x^(2)`
`V(x=1)=9V`
And `V(x=-2)=24V`
Hence, `DeltaV=15V`
`E=-(DeltaV//Deltax)=-10x`
`therefore E(atx=-1m)=10NC^(-1)`
So, `F=qE=+10N` (along positive `x-` axis).