A parallel plate capacitor is charged and the charging battery is then disconnected. If the plates of the capacitor are moved farther apart by means of insulating handles:

Options

A. The charge on the capacitor increases.
B. The voltage across the plates increases.
C. The capacitance increases.
D. The electrostatic energy stored in the capacitor increases.

Answer

B, D

Explanation

b.,d.
As battery is disconnected, hence `Q=` constnat, plates of capacitor are moved apart
Hence `C` decreases `(C=(1)/(d))`
Now, `V=(Q)/(C)` and `U=(Q^(2))/(2C)`
`V="constant",C=KC_(0)` i.e., `CgtC_(0)` ltbgt `Q=CV,` i.e., `QgtQ_(0)`
`U=(1)/(2)CV^(2),` i.e., `UltU_(0)`