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Excess electrons are placed on a small l...

Excess electrons are placed on a small lead sphere of mass `6.90 ` g so that its net charge is `-3.20 xx 10^(-9)C`. Find the number of excess electorns ( in terms of `xx 10^(10))` on the sphere.

Text Solution

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`qq=n_(e)e` or `n_(e)=(-3.20xx10^(-9))/(-1.6xx10^(-9))=2.0xx10^(10)`
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Knowledge Check

  • An ebonite rod acquires a negative charge of 3.2 xx 10^(-10) C. The number of excess electrons it has is given by

    A
    `2 xx 10^9`
    B
    `2 xx 10^(-9)`
    C
    `2 xx 10^(-29)`
    D
    `2 xx 10^(29)`

  • An ebonite rod acquires a negative change of 6.4 xx 10^-10 C . The number of excess electrons it has is

    A
    `4 xx 10^9`
    B
    `4 xx 10^(-9)`
    C
    `4 xx 10^(-29)`
    D
    `4 xx 10^(29)`

  • The electronic charge is 1.6xx10^(-19) coulomb. If a body carries a negative charge of 9.6xx10^(-10) coulombs, what is the number of excess electrons on the body?

    A
    `6xx10^(9)`
    B
    `1//6xx10^(-29)`
    C
    `6xx10^(29)`
    D
    `6xx10^(29)`

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