A positive charge `+q_1` is located to the left of a negative charge `-q_2`. On a line passing through the two charges, there are two places where the total potential is zero. The reference is assumed to be at infinity.The first place is between the charge and is 4.00 cm to the left of the negative charge. The second place is 7.00 cm to the right of the negative charge. If `q_2 = -12muC and q_1 = 11 xx xmuC`, what is the value of x.

Explanation

`(q_(1))/(x-4)-(q_(2))/(4)=0" "(q_(1))/(x+7)-(q_(2))/(7)=0`
or `(q_(1))/(q_(2))=(x-4)/(4)" "(q_(1))/(q_(2))=(x+7)/(7)`
`therefore(x-4)/(4)=(x+7)/(7)`
or `7x-28=4x+28` or `3x=56` or `x=(56)/(3)`
or `(q_(1))/(q_(2))=((56)/(3)+7)/(7)=(11)/(3)`
or `|q_(2)|=+12muc`
or `q_(1)=12xx(11)/(3)=44muC=11xx4muC`