In Young's double-slit experiment, the separation between the slits is d, distance between the slit and screen is `D (D gt gt d)`, In the interference pattern, there is a maxima exactly in front of each slit. Then the possilbe wavelength(s) used in the experiment are

Options

A. `d^(2) // D, d^(2) // 2D, d^(2) // 3D`
B. `d^(2) // D, d^(2) // 3d, d^(2) // 5D`
C. `d^(2) // 2D, d^(2) // 4D, d^(2) // 6D`
D. none of these

Answer

b

Explanation

`S_(2) P - S_(1) P = (dy)/(D) = (d xx (d//2))/(D) = d^(2)/(2D)`
`(d^(2))/(2D) = n lambda`
`lambda = (d^(2))/(2 n D) , n = 1, 2,…`
`y = (d^(2))/(2D), (d^(2))/(4D) , (d^(2))/(6D)`
.