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Light of wavelength lambda = 5890 Å fall...

Light of wavelength `lambda = 5890 Å` fall on a double-slit arrangement having separation `d = 0.2 mm`. A thin lens of focal length `f = 1 m` is placed near the slits. The linear separation of fringes on a screen placed in the focal plane of the lens is

A

3 mm

B

4 mm

C

2 mm

D

1 mm

Text Solution

Verified by Experts

The correct Answer is:
a.

`beta = (Delta lambda)/(d) = (f lambda)/(d) = (1 xx 4890 xx 10^(-10))/(0.2 xx 10^(-3))`
`= 0.29 xx 10^(-2) m = 2.9 mm ~~ 3 mm`
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