Home
Class 12
PHYSICS
In Young's double-slit experiment, the s...

In Young's double-slit experiment, the slit separation is 0.5 mm and the screen is 0.5 m away from the slit. For a monochromatic light of wavelength 500 nm, the distance of 3rd maxima from the 2nd minima on the other side of central maxima is

A

2.75 mm

B

2.5 mm

C

22.5 mm

D

2.25 mm

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the principles of Young's double-slit experiment and the concepts of fringe width, maxima, and minima. ### Step 1: Identify the given values - Slit separation (d) = 0.5 mm = \(0.5 \times 10^{-3}\) m - Distance from the slits to the screen (D) = 0.5 m - Wavelength of light (λ) = 500 nm = \(500 \times 10^{-9}\) m ### Step 2: Calculate the fringe width (β) The formula for fringe width (β) in Young's double-slit experiment is given by: \[ \beta = \frac{\lambda D}{d} \] Substituting the values: \[ \beta = \frac{(500 \times 10^{-9} \text{ m})(0.5 \text{ m})}{0.5 \times 10^{-3} \text{ m}} \] Calculating this gives: \[ \beta = \frac{(500 \times 10^{-9} \times 0.5)}{0.5 \times 10^{-3}} = 500 \times 10^{-6} \text{ m} = 0.5 \text{ mm} \] ### Step 3: Determine the positions of the maxima and minima - The position of the n-th maximum from the central maximum is given by: \[ y_n = n \beta \] - The position of the m-th minimum is given by: \[ y_m = \left(m - \frac{1}{2}\right) \beta \] ### Step 4: Calculate the position of the 3rd maximum For the 3rd maximum (n = 3): \[ y_3 = 3 \beta = 3 \times 0.5 \text{ mm} = 1.5 \text{ mm} \] ### Step 5: Calculate the position of the 2nd minimum For the 2nd minimum (m = 2): \[ y_2 = \left(2 - \frac{1}{2}\right) \beta = \left(1.5\right) \beta = 1.5 \text{ mm} \] ### Step 6: Calculate the distance between the 3rd maximum and the 2nd minimum Since the 3rd maximum is on one side of the central maximum and the 2nd minimum is on the opposite side, the total distance (Δx) between them is: \[ \Delta x = y_3 + y_2 = 1.5 \text{ mm} + 1.5 \text{ mm} = 3.0 \text{ mm} \] ### Final Answer The distance of the 3rd maxima from the 2nd minima on the other side of the central maxima is **3.0 mm**. ---

To solve the problem step by step, we will follow the principles of Young's double-slit experiment and the concepts of fringe width, maxima, and minima. ### Step 1: Identify the given values - Slit separation (d) = 0.5 mm = \(0.5 \times 10^{-3}\) m - Distance from the slits to the screen (D) = 0.5 m - Wavelength of light (λ) = 500 nm = \(500 \times 10^{-9}\) m ### Step 2: Calculate the fringe width (β) ...
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    CENGAGE PHYSICS|Exercise Multiple Correct|8 Videos
  • WAVE OPTICS

    CENGAGE PHYSICS|Exercise Assertion- Reasoning|13 Videos
  • WAVE OPTICS

    CENGAGE PHYSICS|Exercise Subjective|11 Videos
  • THERMODYNAMICS

    CENGAGE PHYSICS|Exercise QUESTION BANK|34 Videos
  • WAVES

    CENGAGE PHYSICS|Exercise QUESTION BANK|38 Videos

Similar Questions

Explore conceptually related problems

In a Young's double slit experiment, the slit separation is 1mm and the screen is 1m from the slit. For a monochromatic light of wavelength 500nm , the distance of 3rd minima from the central maxima is

In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be:

In Young's double slit experiment the slits are separated by 0.24 mm. The screen is 2 m away from the slits . The fringe width is 0.3 cm. Calculate the wavelength of the light used in the experiment.

In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic lightg of wavelength 500 nm is used, what will be the width of each slit for obtaining ten mixima of double slit within the central maxima of single slit pattern ?

In a double slit experiment, the two slits are 1mm apart and the screen is placed 1m away. A monochromatic light of wavelength 500nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single-slit pattern?

In a Young's double slit experiment , the slits are Kept 2mm apart and the screen is positioned 140 cm away from the plane of the slits. The slits are illuminatedd with light of wavelength 600 nm. Find the distance of the third brite fringe. From the central maximum . in the interface pattern obtained on the screen frings from the central maximum. 3

In a double slit experiment , the slit separation is 0.20 cm and the slit to screen distance is 100 cm. The positions of the first three minima, if wavelength of the source is 500 nm is

In Young's double -slit experiment, the slits are 0.5 cm apart and screen is 1m away. The slits are illuminated by sodium light of wavelength 6890 Å . What will be the distance between 3^(rd) bright fringe on one side and 4^(th) bright fringe on other side of central fringe.

A Young's double slit experiment is conducted with slit separation 10mm, where the screen is 2m away from the slits. If wavelength of light used is 6000 Å , answer the following Fringe width in mm is

CENGAGE PHYSICS-WAVE OPTICS-Single Correct
  1. In YDSE, light of wavelength lamda = 5000 Å is used, which emerges in ...

    Text Solution

    |

  2. A double-slit experiment is immersed in a liquid of refractive index 1...

    Text Solution

    |

  3. In Young's double-slit experiment, the slit separation is 0.5 mm and t...

    Text Solution

    |

  4. A light of wavelength 6000 Å shines on two narrow slits separeted by a...

    Text Solution

    |

  5. A plane wavefront travelling in a straight line in vacuum encounters a...

    Text Solution

    |

  6. In Young's double-slit experiment, the wavelength of light was changed...

    Text Solution

    |

  7. Calculate the wavelength of light used in an interference experiment f...

    Text Solution

    |

  8. In Young's double-slit experiment the angular width of a fringe formed...

    Text Solution

    |

  9. In a double-slit experiment, the slits are separated by a distance d a...

    Text Solution

    |

  10. In a Young's double slit experiment using monochromatic light, the fri...

    Text Solution

    |

  11. In YDSE, find the thickness of a glass slab (mu=1.5) which should be...

    Text Solution

    |

  12. In Young's double-slit experiment, the slit are 0.5 mm apart and the i...

    Text Solution

    |

  13. Figure shows two coherent sources S(1) and S(2) emitting wavelength la...

    Text Solution

    |

  14. Two waves of light in air have the same wavelength and are intially in...

    Text Solution

    |

  15. Light from a sources emitting two wavelengths lambda(1) and lambda(2) ...

    Text Solution

    |

  16. The wavefront of a light beam is given by the equation x + 2y + 3x = c...

    Text Solution

    |

  17. As shown in figure waves with identical wavelengths and amplitudes and...

    Text Solution

    |

  18. If the distance between the first maxima and fifth minima of a double-...

    Text Solution

    |

  19. In YDSE, D = 1 m, d = 1 mm, and lambda = 5000 nm. The distance of the...

    Text Solution

    |

  20. Let S(1) and S(2) be the two slits in Young's double-slit experiment. ...

    Text Solution

    |