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In YDSE, D = 1 m, d = 1 mm, and lambda ...

In YDSE, `D = 1 m, d = 1 mm`, and `lambda = 5000 nm`. The distance of the 100th maxima from the central maxima is

A

`(1)/(2) m`

B

`(sqrt(3))/(2)` m

C

`(1)/(sqrt(3))` m

D

does not exist

Text Solution

Verified by Experts

The correct Answer is:
c
For 100th maximum,
`d sin theta = 100 lambda`
`implies sin theta = (100 xx 500 xx 10^(-9))/(1 xx 10^(-3)) = (5 xx 10^(-4))/(10^(-3)) = 0.5 = (1)/(2)`
`:. y = D tan theta = 1 xx tan 30 = (1)/(sqrt3)`
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