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In a double slit experiment instead of t...

In a double slit experiment instead of taking slits of equal widths, one slit is made twice as wide as the other. Then, in the interference pattern

A

the intensities of both the maxima and the minima increases

B

the intensity of maxima increases and the minima has zero intensity

C

the intensity of the maxima decreases and that of minima increases

D

the intensity of the maxima decreases and the minima has zero intensity

Text Solution

Verified by Experts

The correct Answer is:
a

When slits are of equal width:
`I_(max) prop (a + a)^(2) (= 4 a^(2))`
`I_(min) prop (a - a)^(2) (=0)`
When one slit's width is twice that of the other :
`(I_(1))/(I_(2)) = (omega_(1))/(omega_(2)) = (a^(2))/(b^(2)) implies (omega)/(2 omega) = (a^(2))/(b^(2)) implies b = sqrt 2a`
`:. I_(max) prop (a + sqrt 2a)^(2) (= 5.8a^(@))`
`I_(min) prop (sqrt 2a - a^(2)) (= 0.17 a^(2))`
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