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Young's double slit experiment is carrie...

Young's double slit experiment is carried out by using green, red and blue light, one color at a time. The fringe width recorded are `b_(G)`,`b_(R)` and `b_(B)` respectively. Then,

A

`beta_(G) gt beta_(B) gt beta_(R)`

B

`beta_(B) gt beta_(G) gt beta_(R)`

C

`beta_(R) gt beta_(B) gt beta_(G)`

D

`beta_(R) gt b\eta_(G) gt beta_(B)`

Text Solution

Verified by Experts

The correct Answer is:
d

Fringe with `beta = (lambda D)/(d)` Hence, `beta prop lambda`.
As we know `lambda_(R) gt lambda_(G) gt lambda_(B)`
Hence, `beta_(R) gt beta_(G) gt beta_(B)`
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