Find the frequency of light which ejects electrons from a metal surface. Fully stopped by a retarding potential of `3 V`, the photoelectric effect begins in this metal at a frequency of `6xx10^(14)Hz`. Find the work function for this metal. (Given `h=6.63xx10^(-34)Js`).

Explanation

To solve the problem, we need to find the work function of the metal using the information provided about the stopping potential and the threshold frequency. Let's break down the steps:

### Step 1: Understand the Photoelectric Effect Equation
The photoelectric effect is described by the equation:
\[ E = W + K_{\text{max}} \]
where:
- \( E \) is the energy of the incident photons,
- \( W \) is the work function of the metal,
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