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a. A stopping potential of 0.82V is requ...

a. A stopping potential of `0.82V` is required to stop the emission of photoelectrons from the surface of a metal by light of eavelength `4000 A`. For light of wavelength `3000 A`, the stopping potential is `1.85V`. Find the value of Planck's constant. [1 electrons volt (eV)`=1.6xx10^(-19)J]`
b. At stopping potential, if the wavelength of the incident light is kept fixed at `4000 A`, but the intensity of light increases two times, will photoelectric current be botained ? Give reasons for your answer.

Text Solution

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a. `(hc)/(lamda_1)=W+eV_1`.... (i)
`(hc)/(lamda_2)=W+eV_2` ...(ii)
Subtracting, we get
`(hc)/(lamda_2)-(hc)/(lamda_1)=e(eV_2-V_1)`
Here, `c=3xx10^8ms^(-1)`,
`lamda_1=4000A=4xx10^(-7)m`,`V_1=0.82V`
`lamda_2=3000A=3xx10^(-7)m`,`V_2=1.85V`
`hxx3xx10^8((1)/(3xx10^(-7))-(1)/(4xx10^(7)))`
`=1.6xx10^(-19)(1.85-0.82)`
or `hxx3xx10^(8)(1)/(12xx10^(-7))=1.6xx10^(-19)xx1.03`
Therefore, Planck's constant,
`h=(1.6xx10^(-19)xx1.03xx12xx10^(-7))/(3xx10^8)`
`=6.592xx10^(-34)J-s`
b. No, because stopping potential does not depend on intensity of incident light
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