How many time does the electron go round the first bohr orbit of hydrogen atoms in `1 s`?

Explanation

Here we have to fine the frequency which is given as `f = (mZ^(2)e^(4))/(4 epsilon_(0)^(3)h^(3))`
`= (9.1 xx 10^(-31) xx l^(2) xx (1.6 xx 10^(-19))^(4))/(4 xx (8.85 xx 10^(-12))^(2) xx l^(3) xx (6.6 xx 10^(-34))^(3))`
`= 6.62 xx 10^(15)Hz`