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Find the ratio of ionization energy of b...

Find the ratio of ionization energy of bohr 's hydrogen atom doubly liothium ion `(Li^(2))`

Text Solution

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The energy of ground state of Bohr's hydrogen-like atom is `E_(n) = - (13.6)Z^(2)`
The ionization energy is equal in energy of ground state state so `E_(ionization) = (13.6) Z^(2)`
`((E_("ionization"))H)/(E_("ionization")Li^(2+))=(Z_(H))^(2)/((Z_(Li^(2+)))^(2))=(1/3)^(2)Rightarrow1/9`
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