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In figure find which is K(a) and K(beta)...

In figure find which is `K_(a) and K_(beta)`

Text Solution

Verified by Experts

`Delta E = (hc)/(lambda), lambda = (hc)/(Delta E)`
Since energy different of `K_(alpha)` is less than `K_(beta)`
i.e. ,` Delta E_(k _ alpha) lt Delta E_(k _ beta)`, therefore
`lambda_(k_alpha) gt lambda_(k_beta)`
So , peak `1 is K_(beta)` and peak `2` is `K_(alpha)`
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