Home
Class 12
PHYSICS
The key feature of Bohr's spectrum of hy...

The key feature of Bohr's spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton. We will extend this to a general rotational motion to find quantized rotational energy of a diatomic molecule assuming it to be rigid.The rule to be applied is Bohr's quantization condition.
In a `CO` molecule, the distance between `C (mass = 12 a. m. u ) and O (mass = 16 a.m.u)` where `1 a.m.u = (5)/(3) xx 10^(-27) kg , `is close to

A

`2.4 xx 10^(-10) m`

B

`1.9 xx 10^(-10) m`

C

`1.3 xx 10^(-10) m`

D

`4.4 xx 10^(-10) m`

Text Solution

Verified by Experts

`r_(1) = (m_(2) d)/(m_(1) + m_(2)) and r_(2) = (m_(1) d)/(m_(1) + m_(2))`

`l = m_(1) r_(1)^(2) + m_(2) r_(2)^(2)`
`:. d = 1.3 xx 10^(-10) m`
Promotional Banner

Topper's Solved these Questions

  • ATOMIC PHYSICS

    CENGAGE PHYSICS|Exercise dpp-4.1|15 Videos

  • ATOMIC PHYSICS

    CENGAGE PHYSICS|Exercise dpp 4.2|15 Videos

  • ATOMIC PHYSICS

    CENGAGE PHYSICS|Exercise Assertion-reasoning type|1 Videos

  • ALTERNATING CURRENT

    CENGAGE PHYSICS|Exercise QUESTION BANK|65 Videos

  • ATOMS

    CENGAGE PHYSICS|Exercise QUESTION BANK|40 Videos

Similar Questions

Explore conceptually related problems

The key feature of Bohr'[s spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton we will extend this to a general rotational motion to find quntized rotantized rotational energy of a diatomic molecule assuming it to be right . The rate to energy applied is Bohr's quantization condition In a CO molecule, the distance between C (mass = 12 a. m. u ) and O (mass = 16 a.m.u) where 1 a.m.u = (5)/(3) xx 10^(-27) kg , is close to

The key feature of Bohr'[s spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton we will extend this to a general rotational motion to find quntized rotantized rotational energy of a diatomic molecule assuming it to be right . The rate to energy applied is Bohr's quantization condition A diatomic molecute has moment of inertie 1 by Bohr's quantization condition its rotational energy in the n^(th) level (n = 0 is not allowed ) is

The key feature of Bohr'[s spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton we will extend this to a general rotational motion to find quntized rotantized rotational energy of a diatomic molecule assuming it to be right . The rate to energy applied is Bohr's quantization condition it is found that the excitation from ground to the first excited state of rotation for the CO molecule is close to (4)/(pi) xx 10^(11) Hz then the moment of inertia of CO molecule about its center of mass is close to (Take h = 2 pi xx 10^(-34) J s )

Is the angular momentum of an electron in an atom quantized ? Explain

An electron in Bohr's hydrogen atom has an energy of -3.4 eV. The angular momentum of the electron is

The angular momentum of an electron in an orbit is quantized because:

An electron in Bohr's hydrogen atom has angular momentum (2h)/(pi) The energy of the electron is

The M.I. of a diatomic molecule is I. what is its rotational energy in the nth orbit , (where n ne 0) if Bohr's quantization condition is used ?

What is the angular momentum of an electron in Bohr's hydrogen atom whose energy is -0.544 eV ?