A radioactive sample decays by `63%` of its initial value in `10s`. It would have decayed by `50%` of its initial value in .

Options

A. `7s`
B. `14 s`
C. `0.7s`
D. `1.4 s`

Answer

A

Explanation

Given, `N_(2)=(N_(0))/(e) =N_(0) e^(- lambda t)rArr t=(1)/(lambda)=10s`
`:. T_(1//2)=(1n2)/(lambda)=0.693 xx 10~~7s` .