A certain radioactive material can under...

A certain radioactive material can undergo three constant `lambda,2lambda` and `3 lambda`. Then, the effective decay constant `lambda_(eff)` is equal to `n lambda`. What is the value of n?

`6`

` 4`

`2`

` 3`

Text Solution

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The correct Answer is:

`(dN_(A))/(dt)=(- lambda N_(A))+(- 2 lambda N_(A)) +(-2 lambdaN_(A))=-6 lambda N_(A)`.

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