There are two radio nuclei `A` and `B. A` is an `alpha` emitter and `B` a `beta` emitter. Their disintegration constant are in the ratio of `1:2` What should be the ratio of number of atoms of `A` and `B` at any time t so that probabilities of getting alpha and beta particles are same at that instant?

Options

A. `2:1`
B. `1:2`
C. `e`
D. `e^_1`

Answer

A

Explanation

`lambda_(A) lambda_(B) =(1)/(2)`
Probabilites of getting `alpha`- and `beta`- particles are same. Thus, rates of disintegration are equal.
`:. lambda_(A) N_(A) =lambda_(B) N_(B)`
or `(N_(A))/(N_(B)) = (lambda_(B))/(lambda_(A))=2` .