A radioacitve nucleus is being produced at a constant rate `alpha` per second. Its decay constant is `lambda`. If `N_(0)` are the number of nuclei at time `t=0`, then maximum number of nuceli possible are .

Options

A. `(alpha)/(lambda)`
B. `(N_(0) alpha)/(lambda)`
C. `N_(0)`
D. `(lambda)/(alpha+N_(0))`

Answer

a

Explanation

Maximum number of nuclei will be present when rate of decay =rate of formation
or `lambda N=alpha`
`:. N=(alpha)/(lambda)` .