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N(1) atoms of a radioactive element emit...

`N_(1)` atoms of a radioactive element emit `N_(2)` beta partilces per second. The decay cosntant of the element is (in `s^(-1)`)

A

`(N_(1))/(N_(2))`

B

`(N_(2))/(N_(1))`

C

`N_(1) ln(2)`

D

`N_(2) ln(2)`

Text Solution

Verified by Experts

The correct Answer is:
b
Activity of a radioactive substance,
`R =lambda N`
`:. Lambda =(R)/(N)`
Here, `R=N_(2)` particles per second and `N=N_(1)`.
`:. Lambda=(N_(2))/(N_(1))`.
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