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A nucleus .Z^AX emits an alpha-particel...

A nucleus `._Z^AX ` emits an `alpha`-particel. The resultant nucleus emits a `beta^(+)` particle. The respective atomic and mass numbers of the final nucleus will be

A

`Z-3, A-4`

B

`Z-1,A-4`

C

`Z -2 , A-4`

D

`Z, A-2`

Text Solution

Verified by Experts

The correct Answer is:
a

`._Z^AX rarr ._2^4He +._(Z-2)^(A-4)Y`
`._(Z-2)^(A-4)Y rarr e^(+) ._(Z-3)^(A-4)Y' `
During `beta^(+)` emission,
`._TP^1 rarr ._0n^1 +beta^(+)`
The proton changes into neutron. So, charge number decreases by 1 but mass number reamins unchanged.
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