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Atomic mass number of an element is 232 ...

Atomic mass number of an element is `232` and its atomic number is `90`. The end product of this radiaoctive element is an isotope of lead (atomic mass `208` and atomic number `82`.) The number of `alpha`-and `beta` -particles emitted are.

A

`6,3`

B

`6,4`

C

`5,5`

D

`4,6`

Text Solution

Verified by Experts

The correct Answer is:
b

Decreases in mass number `=232 -208 =24`
Number of `alpha`-particles emitted `=(24)/(4=6)`
Due to emission of 6 particles, decreases in charge number is `12`. But actual decrease in number is `8`. Clearly, 4 `beta`- particles are emitted.
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