A newly prepared radioactive nuclide has a decay constant `lambda` of `10^(-6) s^(-1)`. What is the approximate half-life of the nuclide?

Options

A. `1 hour`
B. `1 day`
C. `1 week`
D. `1 month`

Answer

c

Explanation

Decay constant, `lambda =10^(-6) s^(-1)`. The half-life `T_(1//2`) is thus given by
`T_(1//2) =(0.639)/(lambda)=(0.639)/(10^(-6)) =0.639 xx 10^(6) s`
`192.5 h ~~ 8 days =1.14 week ~~ 1 week` .