The nuclear radius of `._(8)O^(16)` is `3 xx10^(-15) m`. If an atomic mass unit is `1.67 xx 10^(-27) kg`, then the nuclear density is approximately.

Options

A. `2.35 xx 10^(17) g cm^(-3)`
B. `2.35 xx 10^(17) kg m^(-3)`
C. `2.35 xx 10^(17) g m^(-3)`
D. `2.35 xx 10^(17) kg mm^(-3)`

Answer

b

Explanation

For nucleus of `._(8)O^(16)`:
Mass`=(16)(1.67 xx 10 -27)kg`
Volume `=(4)/(3) pi R^(3)`
`=(4)/(3) pi (3 xx 10^(-15))^(3) m^(3)`
`=36 pi xx 10^(-45) m^(3)`
`Density =(mass)/(volume)=(16 xx67 xx 10^(-27) kg)/(36 pi xx 10^(-46) m^(3))`
`=2.35 xx 10^(17) kg m^(-3)`.