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The beta - decay process , discovered ar...

The `beta - decay` process , discovered around `1900` , is basically the decay of a neutron `n`. In the laboratory , a proton `p` and an electron `e^(bar)` are observed as the decay product of neutron. Therefore considering the decay of neutron as a two- body decay process, it was predicted theoretically that the kinetic energy of the electron should be a constant . But experimentally , it was observed that the electron kinetic energy has continuous spectrum Considering a three- body decay process , i.e.
` n rarr p + e^(bar) + bar nu _(e) , ` around `1930` , Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino `(bar nu_(e))` to be massaless and possessing negligible energy , and the neutrino to be at rest , momentum and energy conservation principle are applied. From this calculation , the maximum kinetic energy of the electron is `0.8 xx 10^(6) eV` The kinetic energy carried by the proton is only the recoil energy.
What is the maximum energy of the anti-neutrino ?

A

The nucleus `._3^6Li` can emit an alpha particle

B

The nucleus `._(84)^(120) P0` cam emit a proton.

C

Deuteron and alpha particle can undergo complete fusion.

D

The nuclei `._(30)^(70) Zn` and `._(34)^(82) Se` can undergo complete fusion.

Text Solution

Verified by Experts

The correct Answer is:
C
`KE_max of beta^(bar)`
`Q=0.8 xx 10^(6) eV`
`KE_p +KE_(beta^(bar))+KE_(bar(V))=Q`
`KE_p` is almost zero
When `KE_(beta(bar)) =0`
Then `KE_(bat(barv))=Q-KE~=Q`
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The beta - decay process , discoverwd around 1900 , is basically the decay of a neutron (n) in the laboratory , a proton (p) and an electron (e^(bar)) are observed as the decay that the kinetic energy of the electron should be a constant . But experimentally , if was observed that the electron kinectic energy has continuous spectrum Considering a three- body decay process , i.e. n rarr p + e^(bar) + bar nu _(e) , around 1930 , pauli expained the observed (bar nu_(e)) to be massaless and possessing negligible energy , and the neutrino to be at rest , momentum and energy conservation principle are applied from this calculate , the maximum kinectic energy of the electron is 0.8 xx 10^(6) eV The kinectic energy carrect by the proton is only the recoil energy What is the maximum energy of the anti-neutrino ?

The beta -decay process, discovered around 1900 , is basically the decay of a neutron (n) , In the laboratory, a proton (p) and an electron (e^(-)) are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a tro-body dcay process, it was observed that the electron kinetic energy has a continuous spectrum. Considering a three-body decay process i.e., n rarr p + e^(-)+overset(-)v_(e ) , around 1930 , Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino (overset(-)V_(e )) to be massless and possessing negligible energy, and neutron to be at rest, momentum and energy conservation principles are applied. From this calculation, the maximum kinetic energy of the electron is 0.8xx10^(6)eV . The kinetic energy carried by the proton is only the recoil energy. What is the maximum energy of the anti-neutrino?

The beta -decay process, discovered around 1900 , is basically the decay of a neutron (n) , In the laboratory, a proton (p) and an electron (e^(-)) are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a tro-body dcay process, it was observed that the electron kinetic energy has a continuous spectrum. Considering a three-body decay process i.e., n rarr p + e^(-)+overset(-)v_(e ) , around 1930 , Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino (overset(-)V_(e )) to be massless and possessing negligible energy, and neutron to be at rest, momentum and energy conservation principles are applied. From this calculation, the maximum kinetic energy of the electron is 0.8xx10^(6)eV . The kinetic energy carried by the proton is only the recoil energy. If the anti-neutrino has a mass of 3eV//c^(2) (where c is the speed of light) instead of zero mass, what should be the range of the kinetic energy, K of the electron?

The beta - decay process , discoverwd around 1900 , is basically the decay of a neutron (n) in the laboratory , a proton (p) and an electron (e^(bar)) are observed as the decay that the kinetic energy of the electron should be a constant . But experimentally , if was observed that the electron kinectic energy has continuous spectrum Considering a three- body decay process , i.e. n rarr p + e^(bar) + bar nu _(e) , around 1930 , pauli expained the observed (bar nu_(e)) to be massaless and possessing negligible energy , and the neutrino to be at rest , momentum and energy conservation principle are applied from this calculate , the maximum kinectic energy of the electron is 0.8 xx 10^(6) eV The kinectic energy carrect by the proton is only the recoil energy If the - neutrono had a mass of 3 eV// c^(2) (where c is the speed of light ) insend of zero mass , what should be the range of the kinectic energy K. of the electron ?

The decay of a proton to neutron is :

A free neutron decays into a proton, an electron and

In beta- decay, all the emitted electron do not have the same energy the same energy. beta- decay is not a two body decay process.