A particle of mass m and charge q is projected into a region having a perpendicular magnetic field B. Find the angle of deviation fo the particle as it comes out of the magnetic field if the width d of the regions is very smaller then
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The radius of the circular orbit is `r=(mv)/(qB)` The deviation `theta` may be obtained from in as `sin theta =d/r=(dBq)/(mv)` or ` theta =sin^-1((dBq)/(mv))`
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