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A particle of massM and positive charge ...

A particle of mass`M` and positive charge `Q`, moving with a constant velocity ` vec(u_(1)) = 4 hat(i) ms^(-1)`, enters a region of uniform static magnetic field , normal to the ` x-y ` plane. The region of the magnetic field extends from ` x= 0` to ` x = L` for all values of `y`. After passing through this region, the particle emerges on the other side after `10 milliseconds` with a velocity `vec(u_(2)) = 2 (sqrt(3 hat(i) + hat(j))) ms^(-1)` . The correct statement(s) is (are)

A

The direction of the magnetic field is -z direction.

B

The direction of the magnetic field is +z direction.

C

The direction of the magnetic field is `(50piM)/(3Q)` unit.

D

The direction of the magnetic field is `(100piM)/(3Q)` units.

Text Solution

Verified by Experts

The correct Answer is:
(a,c)
So magnetic field is along -ve, z-direction.

Time taken in the magnetic field `=10xx10^-3=(piM)/(6QB)`
`B=(piM)/(6xx10^-3Q)=(000piM)/(60Q)=(50piM)/(3Q)`
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