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A conducting ring of radius r having cha...

A conducting ring of radius r having charge q is rotating with angular velocity `omega` about its axes. Find the magnetic field at the centre of the ring.

Text Solution

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Current in the ring `I=(omegaq)/(2pi)`
Magnetic field `B=(mu_0I)/(2r)=(mu_0 omegaq)/((2pi)xx2r)`
` implies B=(mu_0 omegaq)/(4pir)`
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Knowledge Check

  • A non-conducting disc having unifrom positive charge Q , is rotating about its axis with unifrom angular velocity omega .The magnetic field at the centre of the disc is.

    A
    directed outward
    B
    having magnitude `(mu_(0)Qomega)/(4piR)`
    C
    directed inwards
    D
    having magnitude `(mu_(0)Qomega)/(2piR)`

  • There is a ring of radius r having linear charge density lambda and rotating with a uniform angular velocity omega. the magnetic field produced by this ring at its own centre would be

    A
    `(lambda omega^(2))/(2-mu_(0))`
    B
    `(mu_(0)lambda^(2)omega)/(sqrt2)`
    C
    `(mu_(0)lambda omega)/(2)`
    D
    `(mu_(0)lambda)/(2omega^(2))`

  • A horizontal ring of radius r spins about its axis with an angular velocity omega in a uniform vertical magnetic field of magnitude B . The emf induced in the ring is

    A
    zero
    B
    `pir^(2) omegaB`
    C
    `1/2 Br^(2) omega`
    D
    `Br^(2) omega`
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