Current I flows through a long conducting wire bent at right angle as shown in Fig. Find the magnetic field at point P on the right angle bisector of the angle XOY at distance r form O.

Explanation

`B=(mu_0)/(4pi) I/d(sin theta_1+sin theta_2)`

here, `d=rsin45^@=r/(sqrt2)`
`B=2xx(mu_0)/(4pi) I/((r/sqrt2)) (sin45^@+sin90^@)`
`=2sqrt2 (mu_0)/(4pi) I/r (1/(sqrt2)+1)=(mu_0)/(2pi) I/r(sqrt2+1)`