Home
Class 12
PHYSICS
A closed curve encircles several conduct...

A closed curve encircles several conductors. The line integral `ointvecB.vec(dl)` around this curve is `3.83xx10^-4 Tm.`
(a) What is the net current in the conductor?
(b) If you were to integrated around the curve in the opposite direction, what would be the value of the line integral? Expalin.

Text Solution

Verified by Experts

(a) `oint vecB.vecdl=nu_0I_(encl)=3.83xx10^-4Tm`
`I_(encl)=305A`
(b) `-3.83xx10^-4` since `dvecl` points opposits to `vecB` everywhere.
Promotional Banner

Topper's Solved these Questions

  • SOURCES OF MAGNETIC FIELD

    CENGAGE PHYSICS|Exercise Exercise (subjective )|10 Videos
  • SOURCES OF MAGNETIC FIELD

    CENGAGE PHYSICS|Exercise Exercise (single Correct )|75 Videos
  • SOURCES OF MAGNETIC FIELD

    CENGAGE PHYSICS|Exercise Concept Exercise 2.1|35 Videos
  • SEMICONDUCTOR ELECTRONIC : MATERIALS, DEVICES AND SIMPLE CIRCUITS

    CENGAGE PHYSICS|Exercise QUESTION BANK|12 Videos
  • THERMAL PROPERTIES OF MATTER

    CENGAGE PHYSICS|Exercise Question Bank|40 Videos

Similar Questions

Explore conceptually related problems

A closed cure encircles several conductors. The line integral intB.dI around this curve is 3.83xx10^-7T-m a. What is the net current in the conductors? b. If you were to integrate aroundthe curve in the opposite direction, what would be the value of the line integral?

A current of 1//(4pi) ampere is flowing in a long straight conductor. The line integral of magnetic induction around a closed path enclosing the current carrying conductor is

A: In any magnetic field region the line integral ointvecB.vec(dl) along a closed loop is always zero. R: The magnetic field vecB in the expressioin oint vecB.vec(dl) is due to the currents enclosed only by the loop.

Each of conductors shown in figure carries 2A of current into or out of page. Two paths are indicated for the line integral oint overset(to)(B).overset(to)(d)I . What is the value of the integral for the path (a) and (b).

The line integral of magnetic field vec(B) around any closed path through which current I is flowing is given by oint_(c) vec(B).vec(d) l =

The least positive integral value of 'k' for which there exists at least one line that the tangent to the graph of the curve y=x^(3)-kx at one point and normal to the graph at another point is

a. A conductor in the shape of a square of edge length l = 0.4 m carries a current i=10.0 A . Calculate the magnitude and direction of magnetic field at the centre of the square. b. If this conductor is formed into a single circular turn and carries the same current. what is the value of the magnetic field at the centre.