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A square conducting loop of side length ...

A square conducting loop of side length L carries a current I.The magnetic field at the centre of the loop is

A

independent of L

B

proportional L

C

inversely proportional to L

D

linearly proportional to L

Text Solution

Verified by Experts

The correct Answer is:
C

(c) Magnetic field at the centre due to either arm
`B_1=(mu_0)/(4pi)xxI/(L//2)[sin45^@+sin45^@]`
`(mu_0)/(4pi)xx(2sqrt2l)/L`
Field at centre due to the four arms of the square
`B=4B_1=4xx(mu_0)/(4pi)xx(2sqrt2l)/L`
i.e.,`Bprop 1/L`
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