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A steady current is set up in a cubic ne...

A steady current is set up in a cubic network composed of wires of equal resistance and length d as shown in Fig. What is the magnetic field at centre P due to the cubic network?

A

`(mu_0)/(4pi) (2I)/d`

B

`(mu_0)/(4pi) (3I)/(sqrt2d)`

C

0

D

`(mu_0)/(4pi) ( theta piI)/d`

Text Solution

Verified by Experts

The correct Answer is:
C
(c) Net magnetic field at P will be zero, because the magnetic
field at centre P is cancelled by opposite pairs like AD-EF,
etc.
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Knowledge Check

  • A cube made of wire of equal length is connected to a battery as shown in figure.The magnetic field at the centre of the cube is

    A
    `(12)/(sqrt(2))(mu_(0)I)/(piL)`
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    `(12mu_(0)I)/(sqrt2piL)`
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