A steady current is set up in a cubic ne...

A steady current is set up in a cubic network composed of wires of equal resistance and length d as shown in Fig. What is the magnetic field at centre P due to the cubic network?

A

`(mu_0)/(4pi) (2I)/d`

B

`(mu_0)/(4pi) (3I)/(sqrt2d)`

C

0

D

`(mu_0)/(4pi) ( theta piI)/d`

Text Solution

Verified by Experts

The correct Answer is:

C

(c) Net magnetic field at P will be zero, because the magnetic
field at centre P is cancelled by opposite pairs like AD-EF,
etc.

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