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The magnetic field at the origin due to ...

The magnetic field at the origin due to the current flowing in the wire is

A

`-(mu_0I)/(8pia)(hati+hatk)`

B

`(mu_0I)/(2pia)(hati+hatk)`

C

`(mu_0I)/(8pia)(-hati+hatk)`

D

`-(mu_0I)/(4piasqrt2) (hati-hatk)`

Text Solution

Verified by Experts

The correct Answer is:
C

(c)
`B_(OD)=0`
`B_(OB)=0`
`B_(AB)=(mu_0I)/(4piasqrt2)[cos45^@(-hati)+cos 45^@hatk]`
`(mu_0I)/(8pia)(-hati+hatk)`
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Knowledge Check

  • The resulting magnetic field at the point O due to the current carrying wire shown in the figure:

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    Points out of the page
    B
    points into the page
    C
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    `(mu_(0)I)/(4piR)`
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    `(mu_(0)I)/(4R)-(mu_(0)I)/(4piR)`
    C
    `(mu_(0)I)/(4R)-(mu_(0)I)/(2piR)`
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