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From a cylinder of radius R, a cylider o...

From a cylinder of radius R, a cylider of radius `R//2` is removed, as shown in Fig. Current flowing in the remaining cylinder is I. Then, magnetic field strength is

A

`(mu_0I)/(3piR)` at point B

B

`(mu_0I)/(2piR)` at point A

C

zero at point B

D

zero at point A

Text Solution

Verified by Experts

The correct Answer is:
D

(d) Current density:`rho=1/(piR^2-pi(R//2)^2) implies rho=(4I)/(3piR^2)`

Current in smaller cylinder (if there were): `I_1=rhopi(R/2)^2 =I/3`
For A: `B_A=B_("whole-cylinder")-B_("small-cylinder")`
`implies B_A=0-(mu_0(I/3))/(2pi(R//2))=-(mu_0I)/(3piR)`
For B: `B_B=B_("whole -cylinder")-B_("small-cylinder")`
`=(mu_0(I+I//3)(R//2))/(2piR^2)-0=(mu_0I)/(3piR)`
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